Question

The area of the triangle formed in the first quadrant by the line 3x+4y=12

Answer 1

Answer:

6

Step-by-step explanation:

3x+4y-12=0

area=(c^2)/2|ab|

Answer 2

$\maltese$$\tt{solution:-}\maltese$

the equation of line is 3x+4y-12=0

Dividing the equation both side by 2

then,

$\rightarrow \tt\frac{3x}{12}+\frac{4y}{12}=\frac{12}{12}\\ \rightarrow \tt \frac{x}{4}+\frac{y}{3}=1\\ \tt Area\:of\:the\: triangle=\frac{1}{2}×base×height\\ \rightarrow\tt\frac{1}{2}×4×2\\ \rightarrow \tt{\underline{\fbox{6 sq.unit}}}$