Question

The area of the triangle whose vertices (1, 0),
(7,0) and (4, 4) is​

Answer 1

Answer:

12 sq.unit

Step-by-step explanation:

here,

x1=1. y1=0

x2=7. y2=0

x3=4 y3=4

Area of triangle=1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)

then,

= 1/2(1(0-4)+7(4-0)+4(0-0)

= 1/2(-4+28)

= 1/2(24)

= 12

I hope this answer is correct