Question

the area of trapezium 300 perpendicular distance between two parallel sides 15 metre if the difference of The parallel side is 16 find the length of the parasite​

Answer 1

Answer:

12m and 28m.

Step-by-step explanation:

Area of the Trapezium: 300 m sq.

Perpendicular distance between parallel sides: 15 m

Difference between the two parallel sides: 16m

Let one of the parallel sides be x.

Another parallel sides: (x + 16) {As the difference is 16}

So, area of Trapezium:

$\frac{1}{2} \times ((d1 + d2) \times p) = 300$

$\frac{1}{2} \times ((x + x + 16) \times 15) = 300$

$\frac{1}{2} \times ((2x \: + 16) \times 15) = 300$

$\frac{1}{2} \times (2 \times (x + 8) \times 15) = 300$

(x + 8) × 15 = 300

x + 8 = 300/15

x = 20 - 8

x = 12

So, first Parallel side: x → 12m

Second Parallel side: x + 16 → 12 + 16 → 28m

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