Question

the area of trapezium is 12sq.m. If its height be 3, find the sum of its parallel side

Answer 1

Area of Trapezium,

$\frac{1}{2} \times (sum \: of \: parallel \: sides) \times height$

Now, putting given values,

$\frac{1}{2} \times( sum \: of \: parallel \: sides) \times 3 = 12 \\ sum \: of \: parallel \: sides = \frac{12 \times 2}{3} \\ sum \: of \: parallel \: sides = 8 \: cm$

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