the area of trapezium is 198cm and it's height is 9cm. if one of the parallel sides is longer than the other by 8cm the the two parallel sides are
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19
let one of the parallel side be x cm
other parallel side be x + 8 cm
area of trapezium=1/2 × (Sum of parallel side) × height
198=1/2×(x+ x+ 8)×9
198×2/9=2x + 8
44=2x+ 8
44-8=2x
36=2x
36/2=x
18cm=x
one parallel side=18 cm
other parallel side= 18 + 8=26 cm
other parallel side be x + 8 cm
area of trapezium=1/2 × (Sum of parallel side) × height
198=1/2×(x+ x+ 8)×9
198×2/9=2x + 8
44=2x+ 8
44-8=2x
36=2x
36/2=x
18cm=x
one parallel side=18 cm
other parallel side= 18 + 8=26 cm
Answered by
3
Area of trapezium 1 upon 2 ( sum of its parallel sides) height
198=1 upon 2(x + x +8) 9
198 ×2÷ 9 =(x+x+8)
44=2x + 8
44÷8=2x
5.5= 2x
5.5÷2=x
[2.75=x] answer
[2.75+8= 2x] answer
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198=1 upon 2(x + x +8) 9
198 ×2÷ 9 =(x+x+8)
44=2x + 8
44÷8=2x
5.5= 2x
5.5÷2=x
[2.75=x] answer
[2.75+8= 2x] answer
Please add me to the brainleist
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