Question

the area of trapezium is 270cm² and the altitude is 9cm if one of the side is 6cm longer than the other . find the length of both parallel sides​

Answer 1

Step-by-step explanation:

let the parallel sides be x, x+6

½×(x+x+7)×9=270

½(2x+7)=30

2x+7=60

x=23

sides=23,29

Answer 2

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The area of trapezium is 270cm² and the altitude is 9cm if one of the side is 6cm longer than the other. Find the length of both parallel sides.

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Length of parallel sides are 27m and 33m.

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• Area of trapezium 270cm²
• Altitude = 9cm

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• Parallel sides of trapezium

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Area of trapezium =

$\bf\purple{ \frac{1}{2} \times sum \: of \: ll \: sides \: \times h}$

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Let one parallel side be x

then, other side will be = ( x + 6)

$\bf \: Area \: of \: trapezium ={ \frac{1}{2} \times sum \: of \: ll \: sides \: \times h}$

$\bf \to 270 = \frac{1}{2} (x + x + 6) \times 9$

$\bf \to 270 = \frac{1}{2} (2x + 6) \times 9$

$\bf \to 270 \div 9 = \frac{1}{2} (2x + 6)$

$\bf \to 30 = \frac{1}{2} (2x + 6)$

$\bf \to 30 \times 2 = 2x + 6$

$\bf \to 60 = 2x + 6$

$\bf \to 60 - 6 = 2x$

$\bf \to 54 = 2x$

$\bf \to 54 \div 2 = x$

$\bf \to x = 27m$

(x + 6 ) = 27 + 6 = 33m

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