Math, asked by farhan6515, 1 year ago

the area of trapezium is 385 cm2 and its altitude is 14 cm the difference between parallel side is 5 cm then find their length

Answers

Answered by lohithagandham
9
the lengths are 30cm and 25cm
Attachments:
Answered by wifilethbridge
2

The parallel sides are 30 cm and 25 cm

Step-by-step explanation:

Area of trapezium = \frac{1}{2}(\text{Sum of parallel sides}) \times height

Its altitude is 14 cm

So,Area of trapezium = \frac{1}{2}(\text{Sum of parallel sides}) \times 14

We are given that the area of trapezium is 385 sq.cm.

So,\frac{1}{2}(\text{Sum of parallel sides}) \times 14 =385

\text{Sum of parallel sides} = \frac{385 \times 2}{14}

\text{Sum of parallel sides} = 55

Let the parallel sides be x and y

So, x+y=55 ---1

The difference between parallel side is 5 cm

x-y=5 -----2

Add 1 and 2

2x=60

x=30

x+y=55

30+y=55

y=55-30=25

Hence The parallel sides are 30 cm and 25 cm

#Learn more:

The area of a trapezium is 96 cm2. The length of the parallel sides are 18 cm and 14 cm. Find its height

https://brainly.in/question/8325167

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