Question

The area of trapezium is 475cm square and the height is 19cm find the lengths of its two parallel sides if one side is 4cm greater than the other.

Answer 1

Area of trapezium =475cm^2

height=19cm

Let the two parallel sides be a;b

a=x;b=x+4

Area formula=a+b/2*h

475=x+4+x/2*19

475/19=2x+4/2

25=2(x+2)/2

x+2=25

x=23

a=23cm

b=23+4=27cm


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Answer 2

first side=x
another sides x+4cm
Area of trapezium =475 cm²
height =19 cm
Area of trapezium =½*(sum of parallel side) h
=½*(x+x+4cm)19cm=475 cm²
(x+x+4cm)=475cm²*2/19cm(here we multiple 2 in 475 then we divide the number by 19)
2x+4cm=50cm
2x=50cm-4cm
2x=46
x=46/2
x=23
first parallel side =23-4=19cm
second parallel side =23cm