The area of trapezium is 495 sq cm its parallel sides are in the ratio 4:7 and the perpendicular distance between them is 10 cm .Find the length of each of the parallel sides
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area=1/2(a+b)h
495=1/2(4x+7x)10
495*2=11x*10
45*2=10x
x=9.
so parallel sides are 4x=36 and 7x=63.
495=1/2(4x+7x)10
495*2=11x*10
45*2=10x
x=9.
so parallel sides are 4x=36 and 7x=63.
Answered by
8
Let the common ration be x,
Then the two parallel sides are 3x, 2x
Distance between them = 10 cm
Area of trapezium = 325 cm²
Area of trapezium = 1/2 (p₁ + p₂) h
325 = 1/2 (3x + 2x) 10
⇒ 325 = 5x × 5
⇒ 325 = 25x
⇒ x = 325/25
Therefore, 3x = 3 × 13 = 39 and 2x = 2 × 13 = 26 ,...... just an example I gave it's not your answer so solve it bro
Then the two parallel sides are 3x, 2x
Distance between them = 10 cm
Area of trapezium = 325 cm²
Area of trapezium = 1/2 (p₁ + p₂) h
325 = 1/2 (3x + 2x) 10
⇒ 325 = 5x × 5
⇒ 325 = 25x
⇒ x = 325/25
Therefore, 3x = 3 × 13 = 39 and 2x = 2 × 13 = 26 ,...... just an example I gave it's not your answer so solve it bro
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