the area of trapezium is 912 sq.cm. the length of its parallel sides are in the ratio 6:13and the height is 24cm. find the length of its parallel side
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Answered by
43
Area of Trapezium = 1/2 × ( sum of parallel sides ) × hieght
912 = 1/2 × 6x + 13x × 24
912 = 19x × 12
19x = 912/12
19x = 76
x = 76/19
x = 4
6x = 24cm
13x = 52cm
912 = 1/2 × 6x + 13x × 24
912 = 19x × 12
19x = 912/12
19x = 76
x = 76/19
x = 4
6x = 24cm
13x = 52cm
Answered by
16
Area of trapezium = 1/2*(sum of parallel sides)*height
Given: area = 912 sq.cm.
Height = 24 cm
Lengths of the parallel sides are in the ratio 6:13
Let the sides be 6x and 13x
Now we can substitute these values in the above formula,
912 = (6x+13x)*24/2
912= 19x*12
=> x = 4
Thus the lengths of the parallel sides are
a = 6x = 6*4 = 24cm
b = 13x = 13*4 = 52cm
Given: area = 912 sq.cm.
Height = 24 cm
Lengths of the parallel sides are in the ratio 6:13
Let the sides be 6x and 13x
Now we can substitute these values in the above formula,
912 = (6x+13x)*24/2
912= 19x*12
=> x = 4
Thus the lengths of the parallel sides are
a = 6x = 6*4 = 24cm
b = 13x = 13*4 = 52cm
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