Question

the area of trapezium is
${168cm}^{3 }$
AND ITS HEIGHT IS 8CM . IF ONE SIDE OF THE PARALLEL SUDES IS LONGER THAN THE OTHER BY SIX FIND THE LENGTH OF EACH OF THE PARALLEL SIDE.

Answer 1

Answer :

18 cm and 24 cm.

Step-by-step explanation :

Let the one side of trapezium be x. Then, the other side be ( x + 6 )

We know that ;

Area of trapezium = 1 / 2 × sum of || sides × h

⇒168 =  1 / 2 × ( x + x + 6 ) × 8

⇒ 168 = 4 ( 2x + 6 )

⇒ 168 = 8x + 24

⇒ 8x = 168 - 24

⇒ 8x = 144

⇒ x = 144 / 8

⇒ x = 18

Hence,

One parallel side = x = 18 cm.

Other parallel side = x + 6 = 24 cm.

Answer 2

Here's your answer!!


Solution :-


It's given that ,

Area of Trapezium is =

$= > 168 {cm}^{3}$
And its height is = 8 cm

And ,
One side of parallel side is longer than the other By 6 .


So,


Let the length of one side be x .

So , length of Other side = (x +6)


We know that ,

Area of Trapezium =
$= > \frac{1}{2} \times (sum \: of \: parallel \: side \: ) \times height$

Hence,
A/q ,


$= > 168 = \frac{1}{2} \times (x + x + 6) \times 8$

$= > 168 = (x + x + 6 ) \times 4$

$= > \frac{168}{4} = x + x + 6$

$= > 42 = 2x + 6$

$= > 2x = 42 - 6$

$= > 2x = 36$

$= > x = 18$

Therefore,


Length of one side is =x=18cm .

And length of Other side = (x+6) =(18+6)= 24cm



Hope it helps you!! ^^

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