the area of trapezium is360cmsquare and the perpendicular distance between parallel side is 12cm.if one of the parallel side is longer than other by 6cm,find the length of parallel sides
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are of trapezium= 1/2 (sum of parallel sides) (altitude)
360cmsq. = 1/2 (x+x+6) (12)
360 = 12/2(2x+6)
360 =6(2x+6)
360 = 12x+36
360-36 = 12x
324 =12x
x= 324/12 = 27
2x= 27+12=39cm
360cmsq. = 1/2 (x+x+6) (12)
360 = 12/2(2x+6)
360 =6(2x+6)
360 = 12x+36
360-36 = 12x
324 =12x
x= 324/12 = 27
2x= 27+12=39cm
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