Question

the area of trapezium is50cm².if the ratio of parallel sides is 2:3and the distance between the parallel sides is 10cm, find the length of 2parallel sides

Answer 1

let the common multiple be x , then ;
The parallel sides of the trapezium will be :
a = 2x
b = 3x

h = 10 cm

Area of trapezium = (1/2)×(a+b)×h
50 = (1/2)×(2x+3x)×10
10 = 5x
x = 2

Hence the length of the sides are ;
a = 2x = 2×2 = 4cm
b = 3x = 3×2 = 6 cm
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Answer 2

area of trapezium= 50cm²
1/2( S1+S2 )h = 50cm²
let parallel sides be
S1 = 2x
S2 = 3x
h = 10cm
so,
50cm = 1/2*( 2x + 3x )* 10
50cm = 5 (5x)
50cm = 25x
50/25 = x
2= x
therefore,
2x = 2* 2
= 4cm
= S1
3x = 3*2
= 6 cm
= S2

hence, the length of 2 parallel sides r 4cm and 6cm respectively.