Question

The area of triangle AOB having vertices A( 0,6) ,O ( 0,0) and B ( 6, 0 ) is

Answer 1

Step-by-step explanation:

The area of △(AOB) having vertices A(0,6),O(0,0) and B(6,0) is. Solution : ar(△AOB)=(12×6×6) sq units = 18 sq units

Answer 2

Given:

A(0,6), O(0,0) and B(6, 0)

To find:

The triangle's area

Solution:

The triangle's required area=18 sq units.

We can obtain the area's value by using the vertices' coordinates- A, B, and O.

The vertices are as follows-

A(0,6), O(0,0), B(6, 0)

So, (x1, y1)= (0, 6)

(x2, y2)=(0 ,0)

(x3, y3)=(6, 0)

The required area=1/2× | [x1(y2-y3)+x2(y3-y1)+x3(y1-y2)] |

On using the values, we get

=1/2× | [0(0-0)+0(0-6)+6(0-6)] |

=1/2×| [0+0-36]|

=1/2×|-36|

=1/2×36

=18 sq units.

Therefore, the triangle's required area=18 sq units.