The area of triangle ARF is 1/3 of the area of rectangle ABCD which is 600 sq.m and long side is equal to 60 m . Find the length of the hypotenuse of triangle AEF
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Answer:
The diagonal of a rectangle can be found using the hypotenuse theorem.
⇒AC
2
=AB
2
+BC
2
⇒(2x
2
)=8
2
+6
2
4x
2
=64+36
⇒x
2
=25
∴x=5cm
∴AC=10cm and CE=5cm
From the figure know that AE=15cm,AD=6cm
△DEA is a right angle triangle.
∴DE=
15
2
−6
2
=12.36≅3
17
.
Hence, the answer is 3
17
.
Answered by
1
Step-by-step explanation:
In rectangle ABCD below, AB=5,AF=7, FD=3. Find the following.
(a) Area of ABCD
(b) Area of triangle AEF
(c) Length of BD
(d) Perimeter of ABCD
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