Question

The area of triangle formed by (3,-2),(-2,8) and (0,4) is a 1 sq.unit b 2sq.unit c 0 sq.unit d 4 sq.units

Answer 1

The given three points of  triangle are (3, - 2),(- 2, 8) and (0, 4) .

We have to find, the area of triangle is:

Solution:

We know that,

The area of triangle = $\dfrac{1}{2} [x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})]$

= $\dfrac{1}{2} \times$ [3(8 - 4) - 2(4 + 2) + 0(- 2 - 8)] sq.units

= $\dfrac{1}{2} \times$ [3(4) - 2(6) + 0(- 10)] sq. units

= $\dfrac{1}{2} \times$ [12 - 12 + 0] sq. units

= $\dfrac{1}{2} \times$ [0] sq. units

= 0 sq. units

∴ The area of triangle = 0 sq. units

Thus, the required "option c)  0 sq. units" is correct.