the area of triangle formed by tangents and the chord of contact from (3,4) to y^2=2x is
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Answer:
7√10 sq. units
Step-by-step explanation:
Hi,
Let the chord of contact from P(3, 4) to the parabola S=y² - 2x = 0 be AB.
So, Equation of chord of contact from (3, 4) to parabola y² = 2x , AB will be
S₁ = 0
i.e., 4y - x - 3 = 0
or
x = 4y -3
Finding the point of intersection of line AB with parabola, we get
y² = 2(4y - 3)
=> y² - 8y + 6 = 0
y₁, y₂ are roots
=> (y₁-y₂)² = (y₁+y₂)² - 4y₁y₂
= 8² - 4*6
=40
x₁ = 4y₁-3
x₂ = 4y₂-3
So, length of AB = √(x₁-x₂)² + (y₁-y₂)²
=√17(y₁-y₂)²
=√680,
Also perpendicular distance from point P(3, 4) to the line AB, height of the triangle = |16-3-3|/√4²+1
= 7/√17.
Hence, Area of the triangle
= 1/2* base* height
=1/2*√680*7/√17
=7√10 sq. units
Hope, it helped !
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