Question

the area of triangle formed with x axis x + y =1, x -y + 1 =0 in a square unit

Answer 1

Answer:

Area of the triangle is 1 square units

Step-by-step explanation:

Given lines are

y=0...........(1)

x+y=1.......(2)

x-y=-1......(3)

First we find points of intersection of these lines

solving (1) and (2):

put y=0 in (2) we get

x=1

First vertex of the triangle is A(1,0)

solving (2) and (3):

x+y=1.......(2)

x-y=-1......(3)

2x=0

x=0

put x=0 in (2) we get y=1

Second vertex of the triangle is B(0,1)

solving (3) and (1):

put y=0 in (3) we get

x=-1

Third vertex of the triangle is C(-1,0)

Now,

Area of the triangle ABC

$=\frac{1}{2}*(AC)(OB)$

$=\frac{1}{2}*(2)(1)$

$=1$  square units.