the area of triangle having side 16 cm 63 cm and 65 cm
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Answered by
7
Hey frnd
Here us ur answer❗️❗️❗️
Let base BC=a=63cm, hypo AC=b=65cm.and perpendicular AB= c cm of right angled triangle ABC.
c^2=b^2-a^2=65^2–63^2.
c^2=(65+63)(65–63)
c^2=128×2=256.
c=16 cm.
s=(63+65+16)/2=144/2=72cm.
Area=[s.(s-a) (s-b) (s-c)]^1/2.
=[72(72–63)(72–65)(72–16)]^1/2.
=[72×9×7×56]^1/2.
=[8×9×9×7×7×8]^1/2.
=7×8×9 cm^2.
=504 sq.cm
Hope this helps u♥️♥️
Here us ur answer❗️❗️❗️
Let base BC=a=63cm, hypo AC=b=65cm.and perpendicular AB= c cm of right angled triangle ABC.
c^2=b^2-a^2=65^2–63^2.
c^2=(65+63)(65–63)
c^2=128×2=256.
c=16 cm.
s=(63+65+16)/2=144/2=72cm.
Area=[s.(s-a) (s-b) (s-c)]^1/2.
=[72(72–63)(72–65)(72–16)]^1/2.
=[72×9×7×56]^1/2.
=[8×9×9×7×7×8]^1/2.
=7×8×9 cm^2.
=504 sq.cm
Hope this helps u♥️♥️
adi1423tya:
no
sorry i didn't read it properly
yes it's 36root21
the answer is biven in https://www.quora.com/The-base-of-a-right-angled-triangle-is-63-cm-and-its-hypotenuse-is-65-cm-What-is-the-area-of-a-triangle-using-Herons-formula
Answered by
4
u can find it with help of herons formula
s=a+b+c/2
area = root s (s-a) + s (s-b) +s (s-c)
s=a+b+c/2
area = root s (s-a) + s (s-b) +s (s-c)
answer please
36 root 21
thx .
soory its ans is 216root3
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