Question

the area of triangle having side 16 cm 63 cm and 65 cm

Answer 1

Hey frnd
Here us ur answer❗️❗️❗️

Let base BC=a=63cm, hypo AC=b=65cm.and perpendicular AB= c cm of right angled triangle ABC.

c^2=b^2-a^2=65^2–63^2.

c^2=(65+63)(65–63)

c^2=128×2=256.

c=16 cm.

s=(63+65+16)/2=144/2=72cm.

Area=[s.(s-a) (s-b) (s-c)]^1/2.

=[72(72–63)(72–65)(72–16)]^1/2.

=[72×9×7×56]^1/2.

=[8×9×9×7×7×8]^1/2.

=7×8×9 cm^2.

=504 sq.cm
Hope this helps u♥️♥️

Answer 2

u can find it with help of herons formula
s=a+b+c/2
area = root s (s-a) + s (s-b) +s (s-c)