Question

the area of triangle having side 16 cm 63 cm and 65 cm is ....

Answer 1

I hope this will help u

Answer 2

Step-by-step explanation

Let base BC=a=63cm, hypo AC=b=65cm.and perpendicular AB= 16cm cm of right angled triangle ABC.

s=(63+65+16)/2=144/2=72cm.

Area=[s.(s-a) (s-b) (s-c)]^1/2.

=[72(72–63)(72–65)(72–16)]^1/2.

=[72×9×7×56]^1/2.

=[8×9×9×7×7×8]^1/2.

=7×8×9 cm^2.

=504 sq.cm. . Answer.