Question

the area of triangle whose vertices are (5,0), (8,0) and (8,4) (in sq.units) is

Answer 1

using formula of area of triangle that is
x1(y2-y3)+x2(y3-y1)+x3(y1-y2)
x1=5,x2=8,x3=8
y1=0,y2=0,y3=4
5(0-4)+8(4-0)+8(0-0)
5(-4)+8(4)+8(0)
-20+32+0
12 sq. units