Math, asked by zoya81909, 5 hours ago

the area of triangle whose vertices are A (0,2)B (2,0)and C (0,4)is
(a)1.5sq.units
(b)2sq.units
(c)3sq.units
(d)5sq.units​

Answers

Answered by crankybirds30
1

Step-by-step explanation:

Let A(0, 0), B(3, 0) and C(0, 4) be the vertex and the coordinates of the circumcentre be O(h, k)

We know that OA = OB = OC

(OA)2 = (OB)2 = (OC)2

(h-0)2+ (k-0)2 = (3-h)2 + (0-k)2 = (0-h)2 + (4-k)2

On solving the above equations, we get

h= 3/2 and k= 2

Hence, the coordinates of circumcentre is (3/2, 2).

Similar questions