Question

The area of triangle with given two sides and respectively and perimeter equal to is:​

Answer 1

Answer:

Area= 21 sqrt 11cm square

Step-by-step explanation:

Given:

(i) Perimeter of traingle is 42 cm.

(ii) Measure of two sides of traingle are 18 and 10 cm respectively.

To Find:

(i) What is the area of triangle?

Solution: Let the third side of triangle be x cm. Therefore,

=Sum of all sides= Perimeter

= 18+10+x= 42

= x= 42-28

x= 14 cm { Third side of triangle}

Now, For finding area of triangle we will use

Heron's formula

First find the Semi-Perimeter (s)

= s= ( Sum of all sides/2)

= s= (42/2)

= s= 21

* Formula= sqrt s(s-a) (s-b) (s-c)

= sqrt 21(21-18) (21-10) (21-14)

= sqrt 21(3) (11) (7)

sqrt 3*7*3*11*7

3*7 sqrt 11

21 sqrt 11 cm square

Hence, the area of triangle is 21 sqrt 11 cm square.

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