Question

The area of triangle with vertices (-3,0), (3,0) and (0,k) is 9sq. Units then find k

Answer 1

Answer:

Step-by-step explanation:

two vertices are (-3,0) and (3,0)

and other vertex is on y axis which is (0,k)

so we can consider side on x-axis as base of triangle

and from (0,k) the length of height to the base of triangle will be 'k' units

length of base = 3+3= 6 units

now area of triangle= base × height×$\frac{1}{2}$

∴area = $\frac{1}{2}\times 6\times k$

∴9= $\frac{1}{2}\times 6\times k$

∴k=3.

Answer 2

Answer:

Step-by-step explanation:

area of triangle=1/2×6×k

9=1/2×6×k

k=3