Question

the area of triangleABC=144sq.cm and area of trianglePQR=25sq.cm.Altitude of triangleABC=6cm.If triangleABC-PQR,then the corresponding altitude of trianglePQR is

Answer 1

Answer:

$\frac{area \: of \: abc}{area \: of \: pqr} = \frac{ ({altitude \: of \: trangle \: abc)}^{2} }{ {(altitude \: of \: triangle \: pqr)}^{2} } \\ \frac{144}{25} = \frac{ {6}^{2} }{ {x}^{2} } \\ \frac{144}{25} = \frac{36}{ {x}^{2} } \\ \frac{36 \times 25}{144} = {x}^{2} \\ \frac{6 \times 5}{12} = x \\ \frac{5}{2} = x \\ 2.5 = x$