The area of two equal circles in the figure is 308 Sq.m. find the perimeter of the rectangle.
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Answer is 84 square meter
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2 circles
308÷2=154
πr^2=154
22÷7×r^2=154
22×r^2=154×7
r^2=1078÷22
r^2=49
r=√49
r=7
d=14which is breadth
2d=14×2=28which is length
2( 14+28)= perimeter
28+14×2
42×2=84
308÷2=154
πr^2=154
22÷7×r^2=154
22×r^2=154×7
r^2=1078÷22
r^2=49
r=√49
r=7
d=14which is breadth
2d=14×2=28which is length
2( 14+28)= perimeter
28+14×2
42×2=84
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