Question

the area of two similar triangle ABC and D E F are 16 cm square and 25 CM square respectively.if BC is equals to 2.3 cm find EF

Answer 1

the ratio of area of 2 similar triangle is equal to the square of the ratio of their corresponding side(theorem)
ar(abc)/ar(def)=4square/5square
so the side r in the ratio 4/5
2.3/x=4/5
x=5*2.3/4
=11.5/4
=2.875
hope my answer helps

Answer 2

aloha!

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thank you for asking this question.
here is the answer,

the area of two similar triangles ABC and DEF are given to be 16 cm² and 25 cm².
also, Length of BC is given to be 2.3 cm.

we have got to find the length of EF.

we know that ratio of areas of two similar triangles is equal to the square of ratio of their sides.

so,

$\frac{areaABC}{areaFED} = \frac{ BC^{2} }{ EF^{2} }$

16/25 = 2.3²/ EF²
16/25 = 5.29/ EF²
EF² = 529/ 64
EF = √529/ √64
EF = 23/ 8
EF = 2.875 cm

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hope it helps :^)