Question

the area of two similar triangles are 100 square cm and 64 sq cm.of the altitude of smaller triangle is 4cm . then altitude of the bigger one is​

Answer 1

Answer:

As we know that, for two similar triangles

(Area)₁/(Area)₂ = (side)₁²/(side)₂²

(Area)₁ = 100 cm²

(Area)₂ = 64 cm²

(altitude)₁ = 4 cm

(altitude)₂ = x

100/64 = (4)²/x²

⇒x² = [(16)×64]/100

⇒x = (1024)/100

     =10.24cm

The altitude of the bigger one is 10.24 cm