Question

The area of two similar triangles are 25 and 121 find the ratio of their corresponding sides

Answer 1

⚫Answer

the ratio of the area of the two triangles is equal to ratio of square of their corresponding sides

A1=25

A2= 121

$= > \frac{a1}{a2} = \frac{25}{121}$

let us suppose, sides of two similar triangles are b and c

$= > \frac{a1}{a2} = \frac{( {b})^{2} }{( {c})^{2} }$

$= > \frac{25}{121} = \frac{ {(b)}^{2} }{ {(c)}^{2} }$

$= > \frac{b}{c} = \frac{ \sqrt{25} }{ \sqrt{121} }$

$= > \frac{b}{c} = \frac{5}{11}$

↪b:c=5:11

therefor ratio of their corresponding sides is 5:11

Answer 2

$\boxed{Heya\:mate}$

______________________________

Area of ∆ ABC / Area of ∆ PQR

= (AB / PQ)²

Therefore 

25 / 121 = (AB / PQ)²

(5 / 11)² = (AB / PQ)²

AB / PQ = 5 / 11