Question

The area of two similar triangles are 81cmsquare and 49cmsquare respectively if two altitudes of the bigger triangle is 4.5cmsquare find the corresponding altitude of the smaller triangle

Answer 1

PFA.................

Answer 2

The areas of two similar triangles are in the ratio of the squares of the corresponding altitudes.

Let first triangle altitude be x then second one's is x+10

so, Area of first triangle/area of second triangle=altitude of first triangle/altitude of second triangle

so, 49/64=(x/x+10)²

so, (7/8)²=(x/x+10)²

so, 7/8=x/x+10

so, 7(x+10)=8x

so, 7x+70=8x

so, 7x-8x=-70

so, x=70

So, first triangle's altitude is 70 cm

and the second one's is 80 cm