the area of two similar triangles triangle ABC and triangle PQR and 25 cm^2 and 49 cm^2 respectively ,if QR = 9.8 cm , find BC
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Answered by
31
we know that ratio of the areas of two similar triangle is equal to the square of their ratios of their corresponding sides.
49/25 =(9.8/BC)^2
7/5=9.8/BC
BC=9.8/7*5
=7.0cm
49/25 =(9.8/BC)^2
7/5=9.8/BC
BC=9.8/7*5
=7.0cm
Answered by
9
We know that ratio of the areas of two similar triangle is equal to the square of their ratios of their corresponding sides.
49/25 =(9.8/BC)^2
7/5=9.8/BC
BC=9.8/7*5
=7.0cm
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