Math, asked by akshaychoudhary635, 1 year ago

The area to be measured for painting distemper for an internal surface of a plastered 230 mm thick brick wall having dimension of 3000 mm length and 3200 mm height and having a glazed louvered ventilator of size 600 mm 400 mm in the wall is

Answers

Answered by shubhamjoshi033
6

Answer:

Area of wall which is to be painted distemper will be 9360000 mm²

Step-by-step explanation:

The total surface area of the wall,

A₁ = length x height

=> A₁ = 3000 x 3200 = 9600000 mm²

Area of the ventilator ,

A₂ = 600 x 400 = 240000 mm²

Hence area of wall which is to be painted distemper,

A = A₁ - A₂

=> A = 9600000 - 240000

=> A = 9360000 mm²

Hence area of wall which is to be painted distemper will be 9360000 mm²

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