Question

The areaof a square inscrbed in a circle of radius 8cm is

Answer 1

Answer:

$\large\bold\red{Area = 128\:{cm}^{2}}$

Explanation:

Given,

A square is inscribed in a circle.

Also,

Radius of Circle, r = 8 cm

Therefore,

Diameter of circle will be , d = 16 cm (°.° d = 2r)

Now,

This diameter will be the diagonal of the square.

Let,

The side of square be 'a' cm.

Therefore,

Diagonal of square = √2 a

But,

We have,

$= > \sqrt{2} a = 16 \\ = > \cancel{\sqrt{2} a }= 8 \sqrt{2} \times \cancel {\sqrt{2}} \\ = > a = 8 \sqrt{2}$

Therefore,

Side of square = 8√2 cm

Now,

We know that,

Area of square = ${a}^{2}$

Therfore,

Area = ${(8\sqrt{2})}^{2}=128$

Hence,

$\large\bold{Area = 128\:{cm}^{2}}$

Answer 2

Answer:

128 cm is the correct AnSwEr mate hope it helps you please mark me BRAINLIST