the areaof rectangle carpet is 120 and its perimeter is 46 m the lenght of its diagonal is
keerat124:
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hint , l+b = 23 and lb= 120 (l+ b)=(l+b-2lb=(23)-2×120=289 diagonal =/l+b=/289=/17×17=17
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l*b=120 =area
l+b=23 =perimeter/2
l²+b²=?
(a+b)²=a²+b²+2ab
(l+b)²=l²+b²+2lb
23²=l²+b²+2*120
529-240= l²+b²
289=l²+b²
by Pythagoras theorem
diagonal ²= length²+ breadth ²
diagonal²=289
diagonal=17
lenght of one is diagonal=17
l+b=23 =perimeter/2
l²+b²=?
(a+b)²=a²+b²+2ab
(l+b)²=l²+b²+2lb
23²=l²+b²+2*120
529-240= l²+b²
289=l²+b²
by Pythagoras theorem
diagonal ²= length²+ breadth ²
diagonal²=289
diagonal=17
lenght of one is diagonal=17
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