The areas of cross section of the pump plunger and press plunger of a hydraulic press are 0.04 m2 and
16 m2 respectively.
a. Calculate the force acting on pump plunger if the hydraulic press overcomes a load of 1200 kgf.
b. If the mechanical advantage of the handle is 10, calculate the force applied at the ends of the pump plunger.
Answers
Answer:
Explanation:
Explanation:
Load= 1200 kgf
Area of cross section of the press plunger =a = 16 m2
Area of cross - section of the pump plunger =a ' = 0.04 m2
By Pascal's law,
Pressure exerted by pump plunger = pressure exerted on press plunger.
L / E = a / a'
1200 / E = 16/ 0.04
E = 3 kgf
Force applied at the ends of the pump plunger = 3 /10 = 0.3 kgf
Hope you understand
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Explanation:
Load=900kgf,Effort(E)=?
Area of cross section of the press plunger =a
1
=9m
2
Area of cross - section of the pump plunger =a
2
=0.03m
2
By Pascal's law,
Pressure exerted by pump plunger = pressure exerted on press plunger.
i.e.,
E
L
=
a
2
a
1
⇒
E
900kgf
=
0.03m
2
9m
2
⇒E=
9m
2
900kgf×0.03m
2
=3kgf.