Question

The areas of cross section of the pump plunger and press plunger of a hydraulic press are 0.04 m2 and
16 m2 respectively.

a. Calculate the force acting on pump plunger if the hydraulic press overcomes a load of 1200 kgf.

b. If the mechanical advantage of the handle is 10, calculate the force applied at the ends of the pump plunger.​

Answer 1

Answer:

Explanation:

Explanation:

Load= 1200 kgf

Area of cross section of the press plunger =a = 16 m2

Area of cross - section of the pump plunger =a ' = 0.04 m2

By Pascal's law,

Pressure exerted by pump plunger = pressure exerted on press plunger.

​  L / E =  a / a'

      1200 / E = 16/ 0.04

        E =  3 kgf

Force applied at the ends of the pump plunger = 3 /10 = 0.3 kgf

Hope you understand

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Answer 2

Explanation:

Load=900kgf,Effort(E)=?

Area of cross section of the press plunger =a

1

=9m

2

Area of cross - section of the pump plunger =a

2

=0.03m

2

By Pascal's law,

Pressure exerted by pump plunger = pressure exerted on press plunger.

i.e.,

E

L

=

a

2

a

1

⇒

E

900kgf

=

0.03m

2

9m

2

⇒E=

9m

2

900kgf×0.03m

2

=3kgf.