Question

The areas of equidistantly spaced sections of the underwater form of a small boat are as follows:1.76, 2.78, 3.10, 3.12, 2.61, 1.24, 0.85m2 . Determine the underwater volume if the sections are 3m apart

Answer 1

To solve this problem we will use the Simpson's Volume Formula which is as:

$V=\frac{i}{3}[(A_1+A_7)+4(A_2+A_4+A_6)+2(A_3+A_5)]$

Where "i" is the interval and A's are the underwater areas given in the question.

Plugging in the values we get the above equation to be as:

$V=\frac{3}{3}[(1.76+0.85)+4(2.78+3.12+1.24)+2(3.1+2.61)]$

$\therefore V=2.61+28.56+11.42=42.59$

Thus,  the underwater volume if the sections are 3m apart is 42.59 squared meters.