the areas of the sector of a circle of radius 5cm is 5pie cm find the angle contained by the sector
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Let p is the sustended by the sector
Area of sector = p/360 ×π×5×5
But p/360 ×π×5×5 = 5π
p/360×π= 5π/25=π/5
p/360 = π/5π= 1/5
p =1/5×360
p = 72°
So, the angle subtanded by the sector is 72°
Area of sector = p/360 ×π×5×5
But p/360 ×π×5×5 = 5π
p/360×π= 5π/25=π/5
p/360 = π/5π= 1/5
p =1/5×360
p = 72°
So, the angle subtanded by the sector is 72°
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