Question

The areas of three fields are 165m^2. 195m^2 and 285m^2 respectively. From these, flower beds of equal size are to be made. If the breadth of each bed be 3m, what will be the maximum length of each bed?

Answer 1

Maximum Length of 165 metre Square Garden =

165/3=55m

Maximum Length of 195 metre

Square Garden =

195/3=65m

Maximum Length of 285 metre

Square Garden =

285/3=95m

So the answers are=55m,65m and 95m respectively

Answer 2

The lengths of each bed are 55 m, 65 m, 95 m.

Explanation:

Given : The areas of three fields are 165 m², 195m² and 285m²respectively. From these, flower beds of equal size are to be made. If the breadth of each bed be 3m.

To find : What will be the maximum length of each bed?

Solution :

The area of the field is given by,

$\text{Area}=\text{Length}\times \text{Breadth}$

Area of one field is $A_1=165\ m^2$

Breadth B=3 m

The length is given by,

$L_1=\frac{A_1}{B}$

$L_1=\frac{165}{3}$

$L_1=55\ m$

Area of second field is $A_2=195\ m^2$

Breadth B=3 m

The length is given by,

$L_2=\frac{A_2}{B}$

$L_2=\frac{195}{3}$

$L_2=65\ m$

Area of third field is $A_3=285\ m^2$

Breadth B=3 m

The length is given by,

$L_3=\frac{A_3}{B}$

$L_3=\frac{285}{3}$

$L_3=95\ m$

Therefore, the lengths of each bed are 55 m, 65 m, 95 m.

#Learn more

A park is rectangular in shape. Its length is 500 m and breadth is 300 m. Five square flower bed of size 50 m are dug. Find the remaining area of the park.​

https://brainly.in/question/13926493