Question

the areas of two similar trangles are 100 cm^2 and 64 cm^2 and altitude of first triangle is 20cm then find corresponding altitude of second triangle​

Answer 1

Answer:

let altitude be x

ATQ

100/64 = 20²/ x²

20/x = 10/8

x = 2 multiply 8

x = 16

so the altitude is 16cm