The areas of two similar triangles are 9cm 2 and 16cm 2 the ratio of their corresponding heights is
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Step-by-step explanation:
Let there be two similar triangles T1 and T2
It would have the same base length
Let b1=b2=b
Given:A1=9cm² and A2=16cm²
To find:h1/h2
A1 =b1h1. =9/16
A2 b2h2
h1/H2=9/16
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