Math, asked by kishanoberoy4528, 11 months ago

The areas of two similar triangles are in respectively 9 cm² and 16 cm². The ratio of their corresponding sides is
A. 3:4
B. 4 : 3
C. 2 : 3
D. 4 : 5

Answers

Answered by Shailesh183816
1

\bf\large\underline\green{Answer:-}

A) 3:4

\bf\small\underline\pink{Step- By-Step-Explanation :-}

Ratio of their corresponding sides. We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides. So, the ratio of their corresponding sides is 3 : 4.

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Answered by Anonymous
0

\huge\star\mathfrak\blue{{Answer:-}}

Step-by-step explanation:

Given : The areas of two similar triangles are respectively 9 cm² and 16 cm².

Suppose that ar(△ABC) = 9 cm²

ar(△PQR) = 16 cm²

To find : Ratio of their corresponding sides i.e., BC and QR

ar(△ABC)/ar(△PQR) = BC²/QR² [By theorem]

=> 9/16 = BC²/QR²

=> 3²/4² = BC²/QR²

=> 3/4 = BC/QR

Hence,

Ratio of their corresponding sides = 3 : 4

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