In Fig. 4.239, ΔAHK is similar to ΔABC. If AK = 10 cm, BC = 3.5 cm and HK = 7 cm, find AC. [CBSE 2010]
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Given ΔAHK ~ ΔABC, AK = 10 cm, BC = 3.5 cm and HK = 7 cm.
We know that two triangles are similar if their corresponding sides are proportional.
∴ AC = 5 cm
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