Question

the argument of (1-i)/2​

Answer 1

$- \pi \div 4$

Step-by-step explanation:

z = 1/2-1/2i

comparing with

$z = x + iy$

x = 1/2 and y = -1/2

$arg(z) = {tan}^{ - 1} (y \div x)$

therefore

$arg(z) = {tan}^{ - 1} ( - 1) \\ = - \pi \div 4$