Math, asked by anshikasharma2319, 1 month ago

The art department of a school prepared circular hanging for the annual function of
the school. The circle with diameter 42 cm was placed at the bottom and the size of the middle circle was half the size of the bottom one and the smallest circle was half the size of the middle circle.​
(i)the radius of the small circle is?
(ii)the area of middle circle is?
(iii) the area of bottom circle region that is visible is?
(iv) the ratio of areas of three circles, starting from the bottom circle is?
(v)a colourful tape was used to decorate the boundary of the bottom circle.the length of tape used is?

Answers

Answered by AbhilabhChinchane
0

Answer:

(1) the smallest circle was half the size of the middle circle.

(2) the size of the middle circle was half the size of the bottom one.

(3) The circle with diameter 42 cm was placed at the bottom.

(4) Given that:

Area of three circles are in the ratio 4:9:25

Let the radii of the three circles be a,b and c

We know that the formula for the area of the circle is πr2

We need to find the ratio of their radii hence will take the square root of the areas of the circle

So √4:√9:√25

We get 2:3:5

The radius are in the ratio of 2:3:5

(5) Masking tape, also known as painter's tape, is a type of pressure-sensitive tape made of a thin and easy-to-tear paper, and an easily released pressure-sensitive adhesive. It is available in a variety of widths. It is used mainly in painting, to mask off areas that should not be painted. The adhesive is the key element to its usefulness, as it allows the tape to be easily removed without leaving residue or damaging the surface to which it is applied. The tape is available in several strengths, rated on a 1–100 scale based on the strength of the adhesive. Most painting operations will require a tape in the 50 range. Household masking tape is made of an even weaker paper and lower-grade adhesive.

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