Question

the atea of the triangle formed by the x-axis, the y-axis and the line representing x+y=8(64, 32,16) answer is 32 please tell me method
only no-5 question
please tell me method please ​

Answer 1

Given : triangle formed by the x-axis, the y-axis and the line representing x+y=8

To Find : area of the triangle

Solution:

x  axis   means y = 0

x + y = 8

=> x = 8  

( 8 , 0 ) is intersection the point

y axis means x = 0

x + y = 8

=> y = 8

(0 , 8) is the intersection  point

x  axis   means y = 0

y axis means x = 0

=> ( 0 , 0) is the intersection points

Triangle formed is right angle triangle

with base and height = 8  unit

Area of triangle = (1/2) * base * height

= (1/2) * 8 * 8

= 32  sq units

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Answer 2

SOLUTION

TO DETERMINE

The area of the triangle formed by the x-axis, the y-axis and the line representing x + y = 8

EVALUATION

Here the given equation of the line is

$\displaystyle \sf{x + y = 8}$

We now express it in intercept form as below

$\displaystyle \sf{ \frac{x}{8} + \frac{y}{8} = 1}$

Now the cuts x axis at A(8,0) & y axis at B(0,8)

Graph : Graph is referred to the attachment

Now the line x + y = 8 makes a right angle triangle with coordinate axes ( x axis and y axis )

Hence the required area of the triangle

$\displaystyle \sf{ = \frac{1}{2} \times 8 \times 8 \: \: \: \: sq.unit}$

$\displaystyle \sf{ =32 \: \: \: sq.unit}$

FINAL ANSWER

The area of the triangle formed by the x-axis, the y-axis and the line representing x + y = 8 is 32 sq.unit

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