Question

The atomic mass of 7N15 is 15.000108 any and of 8O16 is 15.994915 amu .If the mass of a proton.is 1.007825 amu.then minimum energy provided to least tightly bound proton is

Answer 1

Energy+ 8O16 → 7N15 + 1H1

[(Mn+ Mh)- Mo] ×931 MeV

[(15.000108+1.007825)-15.994915]×931

=12.11 MeV