Question

the atomic masses of he and ne are 4 and 20 a.m.u. respectively. the value of de broglie wavelength of he gas at –73oc is m times that of the broglie wavelength of ne at 727oc. m is

Answer 1

λHe=hmHeVHeλNe=hmNeVNe=mHeVNemHeVHeλHe=hmHeVHeλNe=hmNeVNe=mHeVNemHeVHe  

M=204×T/M√T/M√M=204×T/MT/M

=204×1000/20√200/4√=204×1000/20200/4

=5×5050−−√=5×5050

= 5

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