The atomic masses of three elements A, B and C having similar chemical
properties are 7, 23 and 39 respectively:
(a) Calculate the average atomic mass of element B according to
Dobereiner’s triads.
(b) Compare the average atomic mass of B with its atomic mass.
(c) What could the elements A, B and C be ?
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Answer:
(a) The average atomic mass of elements A and C =
2
7+39
=
2
46
=23
(b) The average atomic mass of elements A and C is the same as the atomic mass of element B=23.
(c) The element A is Lithium (Li), B is Sodium (Na) and C is Potassium (K). They are Dobereiner's Triads because in Dobereiner's Triads the atomic mass of the middle element is approximately the mean of the atomic masses of other two elements.
Explanation:
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