Question

The atomic no. Of nitrogen ,oxygen and fluorine are 7,8 and 9 respectively.write the electronic configuration of each element and answer the following:(a)out of N,OandF which is most electronegative and which one is least electronegative?(B)what is no. of valence electrons of F?(C)what is the valency of each of N,OandF?

Answer 1

Answer:

a)nitrogen is more electronegative and fluorine is less electronegative

b)the valence electrons of F 7 and valency is 1

c)Valency of N is 3 ,O is 2 and of fluorine is 1

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\fcolorbox{black}{aqua}{Answer:-}$

✏️ a) Fluorine (F) is the most electronegative and Nitrogen (N) is the least electronegative.

✏️ b) Fluorine (F) has 7 valence electrons.

✏️ c) Valency of Nitrogen is 3 and 5, valency of Oxygen is 2, valency of Fluorine is 1.

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I hope this helps! :)