Question

the atomic number of beryllium is 4 while that of oxygen is 8.write down the electronic configuration of the both and deduce their valency from the same.

Answer 1

electronic configuration of beryllium is 2, 2 and electronic configuration of oxygen is 2, 6 valency of Barium is 2 and the valency of Oxygen is -2

Answer 2

Answer:

Explanation:

Atomic number of Beryllium = 4

Electronic configuration = (2, 2)

Atomic number of Oxygen = 8

Electronic configuration = (2, 6)

Valency of Beryllium is 2,

Valency of Oxygen is = 8 ‒ 6 = 2